A snowball has a radius that increases in length at a rate of 1.5 cm per second.
The rate of change of the surface area and volume of the sphere when its radius reaches 40 cm is . . .
The Surface Area :
dL/dr = 8πr
dL/dt = dL/dr × dr/dt=8πr×1,5=12πr
saat r = 40→L = 12×π×40 = 480πcm^2/detik
Volume :
dV/dr = 4πr^2
dV/dt = dV/dr×dr/dt = 4πr^2×1,5 = 6πr^2
When r = 40→V = 6π(40)^2 = 6π(1.600) = 9.600πcm^3/detik.
